Something
public text v1 · immutablea = 0
A = 13591409
B = 545140134
C = 640320
for k in range(0,100):
top = -1^k*fact(6*k)*(A+B*k)
bottom = fact(3*k)*fact(k)^3*C^(3*k+3/2)
a = a + top/bottom
print "a: ", a
print "top:", top
print "bottom:", bottom
print "pi:", 1 / ( 12 * a)