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·published 2008-02-04 16:18 UTC
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Some guys went for a walk (2 hours(having speed M km/h)) and later walk again but (3 hours(having speed same as earlier but just one unit smaller(-1km/h)). Try to find out how big distance they had.


OK my solution:

We know that

s / v = t(distance / speed = time)
now we need to get distance, as we already know speed(not really but)
distance = speed*time

2M = 3(M-1)
2M = 3M -3
-M = -3 / -1
M = 3

now lets find out distance uhm?

(2*3)+(3*2) = 12 km

would it be right, no?