Public feed
#891355
Some guys went for a walk (2 hours(having speed M km/h)) and later walk again but (3 hours(having speed same as earlier but just one unit smaller(-1km/h)). Try to find out how big distance they had.
OK my solution:
We know that
s / v = t(distance / speed = time)
now we need to get distance, as we already know speed(not really but)
distance = speed*time
so
2 3
---- = ----
M M-1
2M-2 = 3M
umm
2M-3M = 2
wtf doesnt make any sense, speed cant be negative, where i went down??