Something
public text v1 · immutablemyInt = 0
storage = ['']
query = ('(one)(two)(three)')
matches = re.findall(query,data)
for storage[myInt] in matches:
print storage[myInt]
myInt += 1
# ---------OR------------
myInt = 0
query = ('(expression1)(expression2)(expression3)')
matches = re.findall(query,data)
for storage in matches: #pretend there are 4 _different_ matches
print storage[myInt]
# -------BOTH SHOW-------
this is match one
this is match one
this is match one
this is match one