Anonymous
public python v1 · immutabledisorder=['b','a','z','a','b','a','z']inorder=[]for i in disorder: inorder.append(i)print disorderinorder.sort()print disorderk=0found=0index=[]alreadythere=0for i in range(len(disorder)): while found != 1: if inorder[i]==disorder[k]: for j in index: if j == k: alreadythere = 1 if alreadythere != 1: index.append(k) found = 1 alreadythere = 0 else: k=k+1 found = 0 print index k=0print disorderprint inorderprint index