Someone

CODE
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#include <iostream>
#include <conio.h>      //getch() funktionen kräver detta!

using namespace std;

int main()
{
    cout << "\n************************************\n";
    cout << "\n*        Blockkalkylator          *\n";
    cout << "\n************************************\n";
    cout << "\n INMATNING AV BLOCKETS DIMENSIONER\n";
    int heltal1, heltal2, heltal3;
    cout << "\nAnge h\x94jd(dm):"; 
    cin >> heltal1;
    cout << "\nAnge l\x84ngd(dm):"; 
    cin >> heltal2;
    cout << "\nAnge bredd(dm):"; 
    cin >> heltal3;
    
    cout << "\nVAL AV MATERIAL\n";
    cout << "\n<1> Marmor\n";
    cout << "<2> Sten\n";
    cout << "<3> Tr\x84\n";
    cout << "Ange number:";

    
    int heltal4;
    heltal4 = getch();
    cin >> heltal4;
    switch (heltal4)
    {
           case '1':
                cout << "Marmor";
                break;
           case '2':
                cout << "Sten";
                break;
           case '3':
                cout << "Tr\x84";
                break;
           default:
                   cout << "Du har inte valt n\x86gon siffra!";
    }

cout << '\n\n\n\n';
cout << "\nMaterial     Volym(dm)      weight(kg)      Price(kr)\n";
cout << "--------       ---------       --------     ---------";

   
cout << "\n\n";
return 0;
}





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I NEED TO DO THIS


Material Weight (kg / dm3) Price (euro / dm3)
Marbel 2,7 20
Stone 2,6 15
Tree 0,6 7


these three item have diffrent price and diffrent weight.

Programming based on for users input: Height, width, length and material, than calculate the volume, weight and price and this must be write out on summary way.

programm must be writte like this exampel:

Add height:4


Add width:5


Add Length:5


(1)Marmor
(2)Sten
(3)Tra
Add number: 2 <<exampel 2 the 2 is stone

Material Volume(dm3) Weight(kg) Price(euro)
-------- --------- -------- --------
Trä 100 260 1500 <<these r the answers