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public text v1 · immutablef(x) = (4x-1) / (2x+3)
y = f(x) = (4x-1) / (2x+3)
y(2x+3) = 4x-1
2xy+3y-4x+1 = 0
x(2y-4)+3y+1 = 0
x(2y-4) = -3y-1
x = -(3y+1) / (2y-4)
finv(x) = -(3x+1) / (2x-4)f(x) = (4x-1) / (2x+3)
y = f(x) = (4x-1) / (2x+3)
y(2x+3) = 4x-1
2xy+3y-4x+1 = 0
x(2y-4)+3y+1 = 0
x(2y-4) = -3y-1
x = -(3y+1) / (2y-4)
finv(x) = -(3x+1) / (2x-4)