All pastes #716656 Raw Edit

Bah

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#716656 ·published 2007-09-27 01:08 UTC
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When you define a variable as the return of a mysql_query() like so:

$variable = mysql_query($query);

And you are wishing to get MULTIPLE returns (loops) of the mysql_fetch_array statement (a.k.a. multiple rows), you CANNOT define it like so.

while ($variable = mysql_fetch_array($variable))

After the first execution of the loop, the content of the $variable variable will be unable to present a valid mysql resource for mysql_fetch_array to reuse after the while statement proceeds with another execution (because there are multiple rows).

There will eventually be an issue with the mysql_fetch_array() call when attempting to present mysql_fetch_array() with a valid mysql resource (as returned from the mysql_query call) because it will be presenting an array return of mysql_fetch_array from the first execution of the while statement.