Anonymous
public text v1 · immutable
a = b = 0
while 1
c = a + b
if (/.*31337.*/.match("#{c}"))
print "#{c}\n"
exit
end
if a == 0 && b == a
a = 1
end
b = a
a = c
c = a + b
end
a = b = 0
while 1
c = a + b
if (/.*31337.*/.match("#{c}"))
print "#{c}\n"
exit
end
if a == 0 && b == a
a = 1
end
b = a
a = c
c = a + b
end