Mine
public text v1 · immutablefor (i = 0; i < 32; ++i){
for (j = 0; j < 4; ++j){
if ((value >> (i + j) & (0x80000000 >> (i + j)) != 0))
printf("1");
else
printf("0");
}
printf("\n");
i += j;
}
////////////////////////OUTPUT BELOW/////////////////////////////
Gimme a value and I'll devide it into 8 4-bit pieces.1
1 is the value
1000
0000
0000
0000
0000
0000
0010