Public feed #531350

Nickman

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·published 2007-06-02 13:32 UTC
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 +--------------------------------------+
 |  Project Numerieke lineaire algebra  |
 |  ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~  |
 |                            Opgave 2  |
 |                                      |
 |  Author  : Nick De Frangh            |
 |            20051401                  |
 |  Date    : 02/06/2007                |
 |  Version : 1.0                       |
 +--------------------------------------+

eps = 2^-50 = 8.881784E-16

K1(A) : 12.000000
K2(A) : 7.256450
KInf(A) : 12.000000

A\B =
  1.00000
  1.00000
  1.00000

Exacte oplossing :
  1.00000
  1.00000
  1.00000

Verschil : X* - X
   -4.4409e-16
   -2.2204e-16
    2.2204e-16

-----

eps = 2^-51 = 4.440892E-16

K1(A) : 12.000000
K2(A) : 7.256450
KInf(A) : 12.000000

A\B =
  1.00000
  1.00000
  1.00000

Exacte oplossing :
  1.00000
  1.00000
  1.00000

Verschil : X* - X
  0

Verschil : X* - X
   -2.2204e-16
    0.0000e+00
    1.1102e-16
eps = 2^-52 = 2.220446E-16
-----
K1(A) : 12.000000
eps = 2^-53 = 1.110223E-16
KInf(A) : 12.000000
K1(A) : 12.000000
K2(A) : 7.256450
KInf(A) : 12.000000
  1.00000
A\B =0000
  1.00000
  1.00000lossing :
  1.00000
  1.00000
Exacte oplossing :
  1.00000- (f)orward, (b)ack, (q)uit
  1.00000
  1.00000

Verschil : X* - X
   -7.7716e-16
   -1.1102e-16
    6.6613e-16

-----

eps = 2^-54 = 5.551115E-17

K1(A) : 12.000000
-- less (100%) (f)orward, (b)ack, (q)uit
KInf(A) : 12.000000

A\B =
  1
  1
  1

Exacte oplossing :
  1.0000
  1.0000
  1.0000

Verschil : X* - X
   0.0000e+00
   0.0000e+00
   1.1102e-16