All pastes #492954 Raw Edit

Miscellany

public text v1 · immutable
·published 2007-05-17 14:54 UTC
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Therefore, the total number of combinations of failed disks that this scheme can support is:

d�p-1C0 + d�p-1C1 + ... + d�p-1Cp-1
= d � (p-1C0 + p-1C1 + � + p-1Cp-1)
= d � 2p-1