全部文本 #4854 原始 编辑

Anonymous

公开 sql v1 · 不可变
·已发布 2005-01-27 17:21 UTC
渲染后的文本正文
SELECT     dbo_Asset_ImageSizes.id, dbo_Asset_ImageSizes.imagename, dbo_Asset_ImageSizes.imagewidth, dbo_Asset_ImageSizes.imageheight,                       dbo_Asset_ProductImages.itemnmbr, Expr4 = 	CASE 	WHEN imageType IS NULL THEN 1	WHEN itemnmbr = 'PCI1802' THEN 1	ELSE 0	ENDFROM         dbo_Asset_ImageSizes LEFT JOIN                      dbo_Asset_ProductImages ON dbo_Asset_ImageSizes.id = dbo_Asset_ProductImages.imageTypeWHERE     CASE 		WHEN imageType IS NULL THEN 1 		WHEN itemnmbr = 'PCI1802' THEN 1 		ELSE 0	  END = 1;