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public c v1 · immutable// Given an array A and the address of element A[x], find the value of x#include <stdio.h>#define TESTVALUE 5int main(void){ int x=TESTVALUE; int A[]={0,1,2,3,4,5,6,7,8,9}; printf("x=%d\n", (&A[x] - &A[0])); return 0;}