Stuff
public text v1 · immutableIn [27]: b=[[a[i], a[i+1], a[i+2]] for i in range(0,len(a)-1,3)]
In [28]: b.append(a[len(a)-len(a)%3:])
In [29]: b
Out[29]: [[1, 2, 3], [4, 5, 6], [7, 8, 9], [0]]In [27]: b=[[a[i], a[i+1], a[i+2]] for i in range(0,len(a)-1,3)]
In [28]: b.append(a[len(a)-len(a)%3:])
In [29]: b
Out[29]: [[1, 2, 3], [4, 5, 6], [7, 8, 9], [0]]