ShadeS

//finds the first value in a 4x4 grid or XxX grid for that matter	

public int FindFirst(String wordToCheck, int StringPos){
		
		
		System.out.println("wordToCheck's first letter : " + wordToCheck.substring(0, 1));
		int LocOfFirstLetter = 23;
	
		for (int x = 0; x < Board.length; x++){
		//	System.out.println("grid @ pos " + x + " is:      String: " + Grid[(x/4)][(x%4)] + " row: " + x/4 + " col: " + x%4);
			String LetterToCheck = wordToCheck.charAt(StringPos)+"";
			System.out.println("Checking Letter : " + LetterToCheck);
			if (LetterToCheck.equalsIgnoreCase(Grid[(x/4)][(x%4)]) == true){			
				System.out.println("First char isOnBoard at location " + Grid[(x/Grid.length)][(x%Grid.length)] + " at r/c : " + x/4 + " " + x%4 );
				LocOfFirstLetter = x;
				SelectedSquare[x]=true;
				FindNext(wordToCheck, StringPos+1, x, (x/Grid.length),(x%Grid.length) );
			}
		}
		return LocOfFirstLetter;
	}
	// suppose to find the next value of the word
	public int FindNext(String wordToCheck, int StringPos, int StartLoc, int row, int col){
		String LetterToCheck = wordToCheck.charAt(StringPos)+"";
		System.out.println("Selected squre should be true: " + SelectedSquare[StartLoc]);
		System.out.println("Next Letter is: " + LetterToCheck);
		System.out.println("First letter at pos: " + StringPos + " row: " + row + " col : " + col);         // is there a way to do this w/o 8 if statements, recursively?
		/*positions to test
		 * 1 row,col-1     left
		 * 2 row-1,col-1   left & up
		 * 3 row-1,col     up
		 * 4 row-1,col+1   up & right
		 * 5 row,col+1     right
		 * 6 row+1,col+1   right & down
		 * 7 row+1,col     down
		 * 8 row+1,col-1   down & left
		 */
		if(row<0 || row > 4 || col <0 || col > 4 ){
			System.out.println("not on board");
		}

		
		return 0;
	}
	
}