rendered paste body// Program about sum, product, division, and riminder.
# include <iostream>
using namespace std;
int main()
{
int num1=0; // integers number1.
int num2=0; // integers number2.
float num3; // float number3.
int sum1; // sum of the number1 and number2.
int prod1; // product of the number1 and number2.
int quot1; // division of the number1 and number2.
int rmd; // riminder of the number1 and number2.
float sum2; // sum of the number1 and number3.
float prod2; // product of the number1 and number3
float quot2; // division of the number1 and number3
cout<< "enter the num1: ";
cin >> num1;
cout<< "enter the num2 (> 8): " ;
cin >> num2 ;
cout <<" num1" << '\t' << "num2" << '\t' << "num3" << '\t';
cout << "sum1" << '\t' << "sum2" << '\t';
cout << "prod1" << '\t' << "prod2" << '\t';
cout << "quot1" << '\t' << "quot2" << '\t';
cout << "rmd" << endl;
cout << num1 << '\t' << num2 << '\t' << num3 << '\t';
cout << sum1 << '\t' << quot2 << '\t' << rmd << endl;
// THIS IS THE PART OF CALCULATION
num3 = num2 * 1.0;
sum1 = num1 + num2 ;
sum2 = num1 + num3 ;
prod1 = num1 * num2 ;
prod2 = num1 * num3 ;
quot1 = num1 / num2 ;
quot2 = num1 / num3 ;
rmd = num1 % num2 ;
cout << num1 << '\t' << num2 << '\t' << num3 << '\t';
cout << sum1 << '\t' << sum2 << '\t' << prod1 << '\t' << prod2 << '\t';
cout << quot1 <<'\t' << quot2 <<'\t' << rmd << endl;
num1=num1 + 5;
num2=num2 - 3;
//PART OF CALCULATION ENDS HERE
// What happen if you repeat the above part again ? but this time see the num1 is not the one you entered, its //the value after the num1+5 is
//performed, so if you repeat this one more time like below what are the results //coming ?
// THIS IS THE PART OF CALCULATION
num3 = num2 * 1.0;
sum1 = num1 + num2 ;
sum2 = num1 + num3 ;
prod1 = num1 * num2 ;
prod2 = num1 * num3 ;
quot1 = num1 / num2 ;
quot2 = num1 / num3 ;
rmd = num1 % num2 ;
cout << num1 << '\t' << num2 << '\t' << num3 << '\t';
cout << sum1 << '\t' << sum2 << '\t';
cout << prod1 << '\t' << prod2 << '\t';
cout << quot1 << '\t' << quot2 << '\t';
cout << rmd << endl;
num1=num1 + 5;
num1=num1 + 5;
num2=num2 - 3;
num2=num2 - 3;
// PART OF CALCULATION ENDS HERE
return 0;
}