Anonymous
public text v1 · immutablel = [1,2,3,4,5,6,7,8,9,10,11,12,13,14]
print "LST: ", l
#if list has elements that dont fit into a 3 item list
#if len(l)%3!=0:
# remainder = l[-(len(l)%3):]
#else:
# remainder = None
items = {}
sub = []
it = 0
count = 0
for each in l:
print "CURRENT: ",each
while count<3:
print "APPENDING: ", l[count]
sub.append(l[count])
count+=1
items["SUB-%s" % count] =sub
print "SUB: ",sub
print "DIC:" ,items
#print "REMAINDER: ", remainder