Mine
public python v1 · immutablecounter = 0for i in range(1,1000): i = str(i) if ('1' in i) or ('3' in i) or ('5' in i) or ('7' in i) or ('9' in i): counter +=1print 1000-countercounter = 0for i in range(1,1000): i = str(i) if ('1' in i) or ('3' in i) or ('5' in i) or ('7' in i) or ('9' in i): counter +=1print 1000-counter