48

/*
Esercizio n° 48;
Funzionamento:

The series, 1^(1) + 2^(2) + 3^(3) + ... + 10^(10) = 10405071317.

Find the last ten digits of the series, 1^(1) + 2^(2) + 3^(3) + ... + 1000^(1000).

Numero troppo grande.
*/
using System;
class NomeProgramma
{
	static void Main()
	{
		double sum1 = 0;
		double sum2 = 0;
		double sum3 = 0;
		for (double i = 1; i <= 1000; i++)
		{
			sum1 += Convert.ToUInt64(Math.Pow(i, i))/3;
			sum2 += Convert.ToUInt64(Math.Pow(i, i))/3;
			sum3 += Convert.ToUInt64(Math.Pow(i, i))/3;
		}
		Console.Write("Somma = {0}\n{1}\n{2}", sum1, sum2,sum3);
	}
}